Torque Calculations: Solve for Disc Revolutions with Opposing Torque

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The discussion focuses on calculating the number of revolutions a disc makes after an opposing torque is applied to slow it down. The initial rotation speed is 8.0 rad/s, and a torque of 14.5 N m is applied. Participants emphasize using Newton's second law for rotation to find angular acceleration. The correct approach involves applying kinematic equations to determine the total revolutions before the disc comes to rest, ultimately leading to an answer of 14 revolutions. The conversation concludes with a participant expressing understanding after receiving guidance.
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Homework Statement
The torque is removed when the disc is rotating at 8.0 rad s-1. An opposing torque of 14.5 N m is applied to slow the disc down. Calculate the number of revolutions the disc makes after the second torque is applied, before it comes to rest.
Relevant Equations
T=Is
W=Wo +at^(2)
W^(2)=Wo^(2) +2aθ
Homework Statement: The torque is removed when the disc is rotating at 8.0 rad s-1. An opposing torque of 14.5 N m is applied to slow the disc down. Calculate the number of revolutions the disc makes after the second torque is applied, before it comes to rest.
Homework Equations: T=Is
W=Wo +at^(2)
W^(2)=Wo^(2) +2aθ

The answer is 14revs
 
Last edited:
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Hint: What's Newton's 2nd law for rotation? (That will allow you to calculate the angular acceleration.)
 
Hi, Thank you for the reply. I know that T=Ia and that it is the sum of Torques that are used in the calculation but I still can't get the answer, can u give me a step by step guide for this question. Thx alot.
 
Now it's your turn to take a crack at solving the problem. Find the angular acceleration, then apply your kinematic formulas. (One of those formulas is exactly what you need.)
 
I get it now thx!
 
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