Multiple torques/forces on a disk, finding net torque

Click For Summary
SUMMARY

The net torque calculation for a 20-cm-diameter disk involves evaluating multiple forces applied at different points. The correct net torque is determined by the equation τnet = τ1 + τ2 + τ3, where τ1 = 30N * 0.1 * sin(90), τ2 = 30N * 0.05 * sin(-45), and τ3 = 20N * 0.05 * sin(-90). The final result is τnet = -0.94 Nm, indicating a counterclockwise rotation. Proper sign management in torque calculations is crucial to avoid errors.

PREREQUISITES
  • Understanding of torque calculations using τ = Frsinφ
  • Familiarity with trigonometric functions, particularly sine
  • Knowledge of rotational dynamics and net torque concepts
  • Ability to interpret force application points on a rotating disk
NEXT STEPS
  • Review the principles of rotational dynamics and net torque calculations
  • Study the effects of force application points on torque in rigid bodies
  • Learn about the significance of sign conventions in physics problems
  • Practice similar problems involving multiple forces and torques on disks
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and rotational motion, as well as educators seeking to clarify torque concepts in practical applications.

aliaze1
Messages
173
Reaction score
1

Homework Statement



The 20-cm-diameter disk in the figure can rotate on an axle through its center.

What is the net torque about the axle?

image: http://session.masteringphysics.com/problemAsset/1000963/5/knight_Figure_13_14.jpg

Homework Equations



τ=Frsinφ

The Attempt at a Solution



τnet= τ1+τ2+τ3+τ4

τ1 = 30N * 0.1 * sin(90)
τ2 = 30N * 0.05 * sin(-45)
τ3 = 20N * 0.05 * sin(-90)
τ4 = 20N * 0.1 * sin(45)
_____________________
τnet =~2.35355 Nm

this was my original solution, which came out incorrect, a friend then told me that τ4 is zero because the force of 20N is not being applied to a point on the disk itself, so then:

τ1 = 30N * 0.1 * sin(90)
τ2 = 30N * 0.05 * sin(-45)
τ3 = 20N * 0.05 * sin(-90)
_____________________
τnet =~0.94 Nm

the issue is that I have only one attempt left at this problem and I want to confirm this before I submit the problem
 
Physics news on Phys.org
That looks kike it should be the right answer, but I think it is less confusing and error prone if you keep the signs out of the sin arguments, in other words if a force is tending to cause conterclockwise rotation, make the entire torgue negative,

eg, T2=-30N*.05m*sin(45)
T3=-20N*0.05*sin(90)

Else it looks fine.
 
got it, yea the signs were messing me up, i got 0.94 when its actually -0.94,

thanks
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 7 ·
Replies
7
Views
20K
  • · Replies 4 ·
Replies
4
Views
5K
Replies
2
Views
8K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 7 ·
Replies
7
Views
8K
  • · Replies 6 ·
Replies
6
Views
22K
  • · Replies 4 ·
Replies
4
Views
9K
  • · Replies 1 ·
Replies
1
Views
5K
Replies
1
Views
10K