Torque is same all along lever?

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Torque is defined as the product of force and the distance from the pivot point, which means it varies with the lever arm length. To maintain equilibrium, the torques around the pivot must be equal, even if the forces applied differ due to varying lever arm lengths. A shorter lever arm requires a greater force to produce the same torque as a longer lever arm. The confusion often arises from conflating torque with force, but they are distinct concepts. Understanding that torque is a measure of rotational force helps clarify why it remains constant at the pivot point while the force needed changes.
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Here's my background so you know where I'm having trouble. I've attached a picture.

I have to find the force produced by the muscle to keep the arm and ball at its current position in the picture. Now, I originally assumed Torque was Force in rotation, and intuitively thought you would need to use more force if you're closer to the pivot (shorter lever arm) than compared to the end (longer lever arm). I was right about force needed being greater as the lever arm got shorter, but I'm having touble understanding why the Torque along the lever must be the same. So, now I know Torque and Force are not the same.
Mathematically, I know there's only one right answer, but how about conceptually? What is torque if it's not force? What does it represent? Why isn't the torque increasing as the lever arm length decreases?

Thanks!
 

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Torque is the perpendicular force times the distance to the pivot point. It is completely different from force. it is F*d.
Given that, you can see that as d decreases, so does the torque.

In this case, in order to hold the weight steady, the two torques must be equal. Because d for the muscle is much less than the other, it requires a much larger force.

does that help?
 
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sorry, it still hasn't clicked. I mean, mathematically I agree with what you've said, but I still can't understand what Torque represents. What is it that makes it the same everywhere along the lever?
 
it is not the same everywhere along the lever. torque is only defined about a pivot point. For the arm to hold the weight steady, the two torques about that point must be equal.

I am at a loss for offering an easy conceptual understanding. I just think of it as F*d.
 
wait I think I've got it now. I was originally thinking of the upward force that the forearm would provide to support the ball, but now I'm thinking of the ball dragging down the forearm. And to balance that we need an upward force and the torques have to equal. Thanks a bunch!
 
you're welcome :)
 
I built a device designed to brake angular velocity which seems to work based on below, i used a flexible shaft that could bow up and down so i could visually see what was happening for the prototypes. If you spin two wheels in opposite directions each with a magnitude of angular momentum L on a rigid shaft (equal magnitude opposite directions), then rotate the shaft at 90 degrees to the momentum vectors at constant angular velocity omega, then the resulting torques oppose each other...

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