Torque on a current loop about a hinge line

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The discussion revolves around calculating the torque on a rectangular current loop hinged at one of its longer sides. The loop has 20 turns, measures 12 by 5 cm, and carries a current of 0.10A in a magnetic field of 0.50T at a 33-degree angle. The torque formula used is T = iAbsin(theta), but there is confusion regarding the moment arm when the hinge is at the side instead of the center. It is suggested that the equation may need to adjust to account for the new hinge position, potentially changing the moment arm from b/2 to b. The conversation emphasizes the importance of understanding the hinge's location for accurate torque calculations.
theowne
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Homework Statement



A rectangular 20 turn loop that is 12 by 5 cm carries a current of 0.10A. It's hinged at one of the longer 12cm sides. It's mounted with its plane at an angle of 33 degrees to the direction of a magnetic field of 0.50T. What's the torque about the hinge line?

Homework Equations



T = iAbsin(theta)

The Attempt at a Solution



I guess my question is about the significance on the hinge line. The example in my book hinges on the z axis located in the middle of loop, so it uses the formula:

t = 2iaB (b/2) sin (theta)
where b/2 sin(theta) is decribed as the "moment arm". When it is hinged on the left longer side instead of the z axis, does this mean the equation would become 2iaB b sin (theta) instead?
 
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Hi theowne ! :smile:

(have a theta: θ :wink:)
theowne said:
The example in my book hinges on the z axis located in the middle of loop, so it uses the formula:

t = 2iaB (b/2) sin (theta)
where b/2 sin(theta) is decribed as the "moment arm". When it is hinged on the left longer side instead of the z axis, does this mean the equation would become 2iaB b sin (theta) instead?

There's various ways of looking a this (including actually working it out from scratch :wink:), but the easiest is probably to add a second loop next to the first, making one big loop with a hinge in the middle! :smile:
 
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