Torque on a sign hung by a hinge

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SUMMARY

The discussion centers on the calculation of torque for a uniform square sign suspended by a hinge. The participant incorrectly applied the torque equation t = F*d*cosx, leading to an erroneous angle of 68 degrees. The correct understanding involves recognizing that the weight of the sign (40 N) exerts a torque about the hinge, and the maximum torque exerted by the hinge is 6.0 N m. The key takeaway is that the torque calculation must account for the weight acting at a distance from the hinge, not just the external force applied.

PREREQUISITES
  • Understanding of torque and net moment concepts
  • Familiarity with the equation T = F * D
  • Knowledge of forces acting on a suspended object
  • Basic principles of rotational dynamics
NEXT STEPS
  • Study the relationship between torque and angular displacement
  • Learn about the effects of friction in hinge mechanics
  • Explore the concept of equilibrium in rotational systems
  • Investigate the role of gravitational force in torque calculations
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in understanding the principles of torque and rotational mechanics, particularly in the context of real-world applications involving hinges and suspended objects.

Physical_Fire
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Homework Statement
A uniform square sign of weight 40 N is suspended vertically from its top edge by a horizontal hinge, as shown. The hinge is not frictionless. When the sign is displaced from the vertical by an external force and then released, it does not return to the vertical position. The maximum torque exerted by the hinge on the sign is 6.0 N m. The sign is displaced by 90 degrees so that it is horizontal and then gradually released. At which angle to the vertical does the sign hang after release? Write out your thought process and understanding as well. (5)
Relevant Equations
T= F*D
Since I understood that torque = net moment, and as it said angle from the vertical, I used the equation t = F*d*cosx. So, 6 = 40*0.4*cosx, x = 68 degrees. I got a zero out of 5 in this question because the thought process was wrong as well as the answer. I do not understand this problem beyond the equations involved. Why is the answer wrong and what is the real concept and understanding behind these problems?

Thanks
 

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Physical_Fire said:
Homework Statement: A uniform square sign of weight 40 N is suspended vertically from its top edge by a horizontal hinge, as shown. The hinge is not frictionless. When the sign is displaced from the vertical by an external force and then released, it does not return to the vertical position. The maximum torque exerted by the hinge on the sign is 6.0 N m. The sign is displaced by 90 degrees so that it is horizontal and then gradually released. At which angle to the vertical does the sign hang after release? Write out your thought process and understanding as well. (5)
Relevant Equations: T= F*D

Since I understood that torque = net moment, and as it said angle from the vertical, I used the equation t = F*d*cosx. So, 6 = 40*0.4*cosx, x = 68 degrees. I got a zero out of 5 in this question because the thought process was wrong as well as the answer. I do not understand this problem beyond the equations involved. Why is the answer wrong and what is the real concept and understanding behind these problems?

Thanks
What was your thought process? Specifically, what does the equation t = F*d*cosx represent? If you set this equal to the maximum torque exerted by the hinge, is the force exerted by the hinge on the sign applied at distance d from the hinge? I think not.

There is an additional force that exerts a torque on the sign. What is its origin?
 
kuruman said:
There is an additional force that exerts a torque on the sign. What is its origin?
Are you referring to weight?
 
Physical_Fire said:
Are you referring to weight?
Yes.
 

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