Torque on a sign hung by a hinge

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Homework Help Overview

The problem involves analyzing the torque on a uniform square sign suspended by a hinge, specifically focusing on the forces and moments acting on the sign when displaced from the vertical position. The context includes understanding the role of torque in relation to the weight of the sign and the hinge's constraints.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • The original poster attempts to apply the torque equation t = F*d*cosx but questions their understanding of the underlying concepts. Participants explore the implications of the hinge's friction and the forces acting on the sign, particularly the weight as a source of torque.

Discussion Status

Participants are actively questioning the assumptions made in the original poster's approach, particularly regarding the application of forces and the definition of torque. There is a recognition of the need to clarify the role of the weight of the sign in the torque calculation.

Contextual Notes

The problem involves a specific setup where the hinge is not frictionless, and the maximum torque exerted by the hinge is given. Participants are discussing the implications of these conditions on the behavior of the sign after being displaced.

Physical_Fire
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Homework Statement
A uniform square sign of weight 40 N is suspended vertically from its top edge by a horizontal hinge, as shown. The hinge is not frictionless. When the sign is displaced from the vertical by an external force and then released, it does not return to the vertical position. The maximum torque exerted by the hinge on the sign is 6.0 N m. The sign is displaced by 90 degrees so that it is horizontal and then gradually released. At which angle to the vertical does the sign hang after release? Write out your thought process and understanding as well. (5)
Relevant Equations
T= F*D
Since I understood that torque = net moment, and as it said angle from the vertical, I used the equation t = F*d*cosx. So, 6 = 40*0.4*cosx, x = 68 degrees. I got a zero out of 5 in this question because the thought process was wrong as well as the answer. I do not understand this problem beyond the equations involved. Why is the answer wrong and what is the real concept and understanding behind these problems?

Thanks
 

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Physical_Fire said:
Homework Statement: A uniform square sign of weight 40 N is suspended vertically from its top edge by a horizontal hinge, as shown. The hinge is not frictionless. When the sign is displaced from the vertical by an external force and then released, it does not return to the vertical position. The maximum torque exerted by the hinge on the sign is 6.0 N m. The sign is displaced by 90 degrees so that it is horizontal and then gradually released. At which angle to the vertical does the sign hang after release? Write out your thought process and understanding as well. (5)
Relevant Equations: T= F*D

Since I understood that torque = net moment, and as it said angle from the vertical, I used the equation t = F*d*cosx. So, 6 = 40*0.4*cosx, x = 68 degrees. I got a zero out of 5 in this question because the thought process was wrong as well as the answer. I do not understand this problem beyond the equations involved. Why is the answer wrong and what is the real concept and understanding behind these problems?

Thanks
What was your thought process? Specifically, what does the equation t = F*d*cosx represent? If you set this equal to the maximum torque exerted by the hinge, is the force exerted by the hinge on the sign applied at distance d from the hinge? I think not.

There is an additional force that exerts a torque on the sign. What is its origin?
 
kuruman said:
There is an additional force that exerts a torque on the sign. What is its origin?
Are you referring to weight?
 
Physical_Fire said:
Are you referring to weight?
Yes.
 

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