Torque- rigid objects in equalibrium/ center of gravity.

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Homework Help Overview

The problem involves a uniform door that is attached to a wall via two hinges. The door's dimensions and weight are provided, and the task is to analyze the forces acting on the door, particularly focusing on the horizontal components of the forces at the hinges and the torque involved in the system.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the application of torque equations and the selection of a pivot point for analysis. There is uncertainty about how to begin the calculations and whether to consider the x components of the forces at the hinges.

Discussion Status

Some guidance has been offered regarding the assumption of gravity acting at the center of the door and the need to find the torque about the lower hinge. Multiple interpretations of the problem setup are being explored, particularly concerning the axis of rotation.

Contextual Notes

Participants are working within the constraints of a homework assignment, which may limit the information they can use or the methods they can apply. There is a focus on understanding the forces and torques without providing direct solutions.

utnip123
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Homework Statement


A uniform door(.81m wide and 2.1m high) weighs 140N and is hung on two hinges that fasten the long left side of the door to a vertical wall. The hinges are 2.1m apart. Assume that the lower hinge bears all the weight of the door. Find the magnitude and direction of the horizontal component of the force applied to the door by a) the upper hinge and the lower hinge. Determine the magnitude and direction of the force applied by the door to b) the upper hinge and the lower hinge.

Fg = 140 N

Homework Equations


ƩT = F L
am stuck on how the torque equation applies to this problem

The Attempt at a Solution


i drew the diagram of the door and the hinges spaced 2.01 m apart.
I think you have to make the pivot point/axle point at the bottom hinge

sum of the vertical forces = weight of the door, I am assuming this.
Am not sure how to even begin this question. but do i start to make x components at the hinges?

any advice would be helpfull.

thanks
 
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utnip123 said:

Homework Statement


A uniform door(.81m wide and 2.1m high) weighs 140N and is hung on two hinges that fasten the long left side of the door to a vertical wall. The hinges are 2.1m apart. Assume that the lower hinge bears all the weight of the door. Find the magnitude and direction of the horizontal component of the force applied to the door by a) the upper hinge and the lower hinge. Determine the magnitude and direction of the force applied by the door to b) the upper hinge and the lower hinge.

Fg = 140 N

Homework Equations


ƩT = F L
am stuck on how the torque equation applies to this problem


The Attempt at a Solution


i drew the diagram of the door and the hinges spaced 2.01 m apart.
I think you have to make the pivot point/axle point at the bottom hinge

sum of the vertical forces = weight of the door, I am assuming this.
Am not sure how to even begin this question. but do i start to make x components at the hinges?

any advice would be helpfull.

thanks
Hello utnip. Welcome to PF !

Assume that gravity acts downward on the door at its center. That will produce a torque about the hinges. Find the torque about the lower hinge.
 
See image below
 

Attachments

but where is your axis on the door?
 

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