1. The problem statement, all variables and given/known data A door, essentially a uniform rectangle of height 2.00 m, width 0.87 m, and weight 130.0 N, is supported at one edge by two hinges, one 35.1 cm above the bottom of the door and one 164.9 cm above the bottom of the door. Calculate the horizontal components of the forces on the two hinges. Lower Hinge: Magnitude, direction Upper Hinge: Magnitude, direction 2. Relevant equations COM for uniform mass should be right in the middle (coordinates .435, 1) Through pythagorean theorem, D distance from COM to Lower hinge: (1-.351)=.649 (.649^2+.435^2)^1/2=.7813 m Same for D to upper hinge. M=W/g=130/9.81=13.25 N I com= 1/2mh^2 Moment of inertia for door using parallel axis theorem: 1/2 mh^2+ md^2 In static equilibrium, all forces must add up to zero. 3. The attempt at a solution First I tried calculating the Moment for each hinge, and that didn't work. Conceptually, I know that the the Weight should be counterbalanced in some way by the moment of inertia on the door by the hinges. (I don't think the normal force on the hinges factors in here) You can't get a horizontal force from the weight of the door, and I'm having trouble deriving one from the Moment. Sorry there isn't more work here---a hint or a push in the right direction would be greatly appreciated. Thanks.