Torque/Rotational Dynamics HW Problem

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SUMMARY

The problem involves a uniform thin rod of weight W = 100 N supported by two vertical props. When one support is removed, the immediate force on the remaining support must be calculated. The correct approach involves analyzing the torque about the pivot point, leading to the conclusion that the force on the remaining support is 100 N, as it must counteract the entire weight of the rod immediately after the other support is removed. This scenario exemplifies principles of rotational dynamics and torque calculations.

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Homework Statement



A uniform thin rod of weight W = 100 N is supported horizontally by two vertical
props at its ends. At time t = 0 one of the these supports is kicked out. Find the
force on the other support immediately thereafter.


Homework Equations



Sum of forces??


The Attempt at a Solution



I really don't understand how to even approach this problem. My guess is that its 50 N because each support holds half of the rod. Any help would be greatly appreciated !
 
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Ok , I have a new guess now lol... 100N, since it is the only remaining force acting in the + y direction
 
I think your first guess was right, but I don't know how to solve this one.
I think it is a rotational motion question. It will rotate about the supported end. You can calculate the torque about that pivot and then find the angular acceleration. That is pretty much a complete description of the initial motion. What if you figure out from the rotational motion how the center of mass accelerates down and say it should fall the same way using F = ma where F is the total of the pivot force and the mg force?
 

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