What Happens to the Remaining Support When One Is Removed From a Supported Rod?

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SUMMARY

The discussion centers on the mechanics of a uniform thin rod supported by two vertical props, specifically analyzing the force on the remaining support when one is removed. The rod, weighing 100 N, is initially in equilibrium with forces F1 and F2, where F1 + F2 = mg. Upon the removal of one support, the force on the remaining support (F1) immediately becomes 100 N, indicating that the entire weight of the rod is now supported by a single prop. This scenario illustrates the principles of static equilibrium and the immediate effects of dynamic changes in support conditions.

PREREQUISITES
  • Understanding of static equilibrium principles
  • Familiarity with Newton's laws of motion
  • Basic knowledge of forces and moments in mechanics
  • Ability to apply equations of equilibrium (e.g., F1 + F2 = mg)
NEXT STEPS
  • Study the concept of static equilibrium in greater detail
  • Learn about the effects of dynamic loads on structures
  • Explore the principles of moments and torque in mechanics
  • Investigate real-world applications of support removal in engineering structures
USEFUL FOR

This discussion is beneficial for physics students, engineering students, and professionals in structural engineering or mechanics who are interested in understanding the behavior of structures under changing support conditions.

EndoBendo
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Homework Statement



A uniform thin rod of weight W = 100 N is supported horizontally by two vertical
props at its ends. At time t = 0 one of the these supports is kicked out. Find the
force on the other support immediately thereafter.

Homework Equations



F1 + F2 = mg


The Attempt at a Solution



-F1(L) + 100N(L) = 0
100N = F1

seems too simple.. i don't understand what i did, i just plugged it into a formula i found in the book...
 
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EndoBendo said:

Homework Statement



A uniform thin rod of weight W = 100 N is supported horizontally by two vertical
props at its ends. At time t = 0 one of the these supports is kicked out. Find the
force on the other support immediately thereafter.

Homework Equations



F1 + F2 = mg


The Attempt at a Solution



-F1(L) + 100N(L) = 0
100N = F1

seems too simple.. i don't understand what i did, i just plugged it into a formula i found in the book...

Once one support is kicked out it is no longer a stable/stationary rod.
 

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