I need help with the following question. 1. A uniform ladder of mass M and length L leans at an angle A against a frictionless wall. If the coefficient of static friction between the ladder and the ground is Q, what is the minimum angle at which the ladder will not slip? Answer so far: let T stand for torque Tladder + TNwall = 0 rFcosA + rFsinA = 0 LFcosA = -LFsinA mgcosA / sinA = Ffriction mg = FfrictiontanA (1 / QcosA) = tanA A = tan^-1(1 / QcosA) *The real answer is supposed to be A = tan^-1(1 / 2Q) I was wondering if you could tell me what I did wrong, and what I should do to get the right answer. Thanks!