I need help with the following question.(adsbygoogle = window.adsbygoogle || []).push({});

1. A uniform ladder of mass M and length L leans at an angle A against a frictionless wall. If the coefficient of static friction between the ladder and the ground is Q, what is the minimum angle at which the ladder will not slip?

Answer so far:

let T stand for torque

Tladder + TNwall = 0

rFcosA + rFsinA = 0

LFcosA = -LFsinA

mgcosA / sinA = Ffriction

mg = FfrictiontanA

(1 / QcosA) = tanA

A = tan^-1(1 / QcosA)

*The real answer is supposed to be A = tan^-1(1 / 2Q)

I was wondering if you could tell me what I did wrong, and what I should do to get the right answer. Thanks!

**Physics Forums | Science Articles, Homework Help, Discussion**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Homework Help: Torque / Static Equilibrium Question

**Physics Forums | Science Articles, Homework Help, Discussion**