Torsional checking for Steel angle member

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SUMMARY

The discussion focuses on the torsional checking of a steel angle member, specifically a 200x150x12 S275 Grade angle subjected to a twisting moment of 30kNm over a 3m span with fixed ends. The key equation used is θ = T L / J G, where T is the twisting moment, L is the length, J is the polar moment of inertia, and G is the shear modulus. To determine adequacy, the maximum shear stress (Tc/J) must be calculated and compared against the allowable shear stress of the S275 material, acknowledging that angle sections are generally poor in torsion due to potential twisting and warping.

PREREQUISITES
  • Understanding of torsion in structural members
  • Familiarity with shear stress calculations
  • Knowledge of polar moment of inertia (J) for angle sections
  • Basic principles of material properties, specifically for S275 steel
NEXT STEPS
  • Calculate the polar moment of inertia (J) for the 200x150x12 S275 angle section
  • Learn about the shear modulus (G) for S275 steel
  • Explore methods to minimize torsional effects in steel angle members
  • Review design codes related to torsion in structural steel design
USEFUL FOR

Structural engineers, civil engineering students, and professionals involved in the design and analysis of steel structures, particularly those focusing on torsional effects in angle members.

wkh023002
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Homework Statement



I meet a problem below:

To check if the angle :200x150x12 S275 Grade can take a twist of 30kNm (on plan ) with Span 3m fixed end connected.

Homework Equations


θ = T L / J G

The Attempt at a Solution


My question is that even I got the angle of twist for this member??
how can i check against design twist (30kNm) to see if it is adequate ?
 
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Well this case should generally be avoided because angle sections are not very good in torsion. What you are looking for is the max shear stress in the member, Tc/J, where T is the twisting moment, c is the angle thickness, and J is the polar moment of inertia often calculated by summing the values of 'bt^3/3' for each leg, where b is the appropriate leg width. Then compare that stress to the allowable shear stress of the material. Note that the steel angle section will both twist and warp. I haven't done such a calculation since school days.
 

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