A solid sphere of mass 0.599 kg rolls without slipping along a horizontal surface with a translational speed of 5.07 m/s. It comes to an incline that makes an angle of 37.0° with the horizontal surface.(adsbygoogle = window.adsbygoogle || []).push({});

(a) What is the total energy of the rolling sphere? Neglect energy losses due to friction.

(b) To what vertical height above the horizontal surface does the sphere rise on the incline?

To find the total energy of a rolling sphere...

(1/2)mv^2 + (1/5)mv^2

but how would i incorporate 37 degrees?

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# Total energy

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