# Total energy

1. Nov 10, 2006

### kbyws37

A solid sphere of mass 0.599 kg rolls without slipping along a horizontal surface with a translational speed of 5.07 m/s. It comes to an incline that makes an angle of 37.0° with the horizontal surface.

(a) What is the total energy of the rolling sphere? Neglect energy losses due to friction.
(b) To what vertical height above the horizontal surface does the sphere rise on the incline?

To find the total energy of a rolling sphere...
(1/2)mv^2 + (1/5)mv^2
but how would i incorporate 37 degrees?

2. Nov 10, 2006

### OlderDan

Maybe you don't have to

3. Nov 11, 2006

### QuantumCrash

It only makes a difference if you have to take friction into account.

4. Nov 11, 2006

You'll need the angle in (b).

5. Nov 11, 2006

### OlderDan

Can you convince me?

6. Nov 11, 2006

### QuantumCrash

It is not necessary for the 'vertical' height. Unless you take into account other forces which makes it more complicated. But then, it does matter.

7. Nov 11, 2006