Two protons are held fixed at a distance of 3 angstroms (3 x 10-10 m) from
one another. The protons have a charge of +1.6 x 10-19 C. After they are released they
repel each other and fly apart and each acquires some kinetic energy. What is the final
total kinetic energy of the two particles when they are at a large distance from each other?
Potential Electric Energy= (1/4pie)*q1q2/r
The Attempt at a Solution
3A * (3e-10m/1 A) = 9e-10m
Ue=(9e9 Nm^2/C^2)(1.6e-19C)(1.6e-19C)/(9e-10m)= 2.56e-19 Nm
And I know that as r goes to infinity, potential energy goes to 0
But the answer is 7.7e-19, what i am doing wrong, what step am I missing thank you!