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It means thar if you draw a line from the origin to the point, the particle moves at right angles to that line - neither towards nor away from the origin.Davidllerenav said:But what does that mean?
It means thar if you draw a line from the origin to the point, the particle moves at right angles to that line - neither towards nor away from the origin.Davidllerenav said:But what does that mean?
So it only changes its directio, right? And how would it be when it only changes its magnitude?haruspex said:It means thar if you draw a line from the origin to the point, the particle moves at right angles to that line - neither towards nor away from the origin.
Well, you had the answer to that in post#1, but I suppose you are looking for an analytical approach.Davidllerenav said:So it only changes its directio, right? And how would it be when it only changes its magnitude?
haruspex said:Well, you had the answer to that in post#1, but I suppose you are looking for an analytical approach.
The only thing I can think of is to write the vector in coordinates. I don't see a neat vector approach.
Nearly. The right hand side needs to be a vector too.Davidllerenav said:Somethinh like ##\vec r = r cos \theta + r sin \theta##?
Well if the direction doesn't change it is a one dimesional movement, so de y coordinate is 0haruspex said:Nearly. The right hand side needs to be a vector too.
And if the direction doesn't change then ...?
Coordinate directions are arbitrary. You can choose coordinates such that the x coordinate is the direction of movement, but it does not have to be that way.Davidllerenav said:Well if the direction doesn't change it is a one dimesional movement, so de y coordinate is 0
Then it would be ##}\vec r = \vec r cos \theta + \ vec r sin \theta##?haruspex said:Nearly. The right hand side needs to be a vector too.
And if the direction doesn't change then ...?
No, that can't be right either. You could rewrite that as ##\vec r = \vec r (\cos \theta + \sin \theta)##, i.e ##(\cos \theta + \sin \theta)=1##.Davidllerenav said:Then it would be ##\vec r = \vec r \cos \theta + \vec r \sin \theta##?
If the direction doesn't change, it only moves in an stright line, thus the magnitude changes, right?
You almost got there with this post but not quite. Look at #40 by @haruspex and write the right hand side of the equation as a vector. This means find expressions for ##r_x## and ##r_y## such that ##\vec r=r_x~\hat i+r_y~\hat j.## Note that once you choose the coordinate system, the Cartesian axes are fixed and so are the unit vectors ##\hat i~## and ##\hat j~##. Therefore in general when vector ##\vec r## changes, only ##r_x## and ##r_y## change and not the unit vectors. The question before you then is "how should ##r_x## and ##r_y## change in particular so that the direction of ##\vec r## remains constant?" You can find an analytical expression describing that either in terms of ##r_x## and ##r_y## or in terms of ##\theta## and ##r##, whichever you think is easier.Davidllerenav said:Somethinh like ##\vec r = r cos \theta + r sin \theta##?
Oh, I see thanks, I will try to describe ##r_x## or ##r_y## on terms of ##\theta## and ##r##, I'll post when I do it.kuruman said:You almost got there with this post but not quite. Look at #40 by @haruspex and write the right hand side of the equation as a vector. This means find expressions for ##r_x## and ##r_y## such that ##\vec r=r_x~\hat i+r_y~\hat j.## Note that once you choose the coordinate system, the Cartesian axes are fixed and so are the unit vectors ##\hat i~## and ##\hat j~##. Therefore in general when vector ##\vec r## changes, only ##r_x## and ##r_y## change and not the unit vectors. The question before you then is "how should ##r_x## and ##r_y## change in particular so that the direction of ##\vec r## remains constant?" You can find an analytical expression describing that either in terms of ##r_x## and ##r_y## or in terms of ##\theta## and ##r##, whichever you think is easier.
What I suggest is not really different from the suggestion by @Delta2 in #43 which implies writing ##\hat r~## in terms of Cartesian unit vectors. The point is that the direction of ##\hat r## depends on ##\theta## so if you want to express a fixed direction analytically, you need to express it in terms of fixed (Cartesian) unit vectors.