Transfer characteristic of this circuit

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SUMMARY

The discussion centers on analyzing the transfer characteristics of a circuit involving diodes and input/output voltage relationships. When the input voltage is between +5V and -5V, the output voltage matches the input due to reverse-biased diodes. For input voltages exceeding +5V, the forward-biased diode conducts, altering the output voltage. The use of Kirchhoff's Voltage Law is suggested to derive the relationship between input and output voltages, emphasizing the need for a current formula based on input voltage (Vi).

PREREQUISITES
  • Understanding of diode behavior in circuits
  • Familiarity with Kirchhoff's Voltage Law
  • Basic circuit analysis techniques
  • Knowledge of voltage and current relationships in electrical engineering
NEXT STEPS
  • Study diode characteristics and their impact on circuit behavior
  • Learn to apply Kirchhoff's Voltage Law in complex circuits
  • Explore current-voltage relationships in diode circuits
  • Investigate circuit simulation tools for visualizing voltage transfer characteristics
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Electrical engineers, circuit designers, and students studying semiconductor devices will benefit from this discussion, particularly those focusing on diode applications and circuit analysis techniques.

Flying_Dutchman
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Homework Statement
What would be the input voltage and output voltage relation for input voltage values
1. -5<Vi<5
2. Vi<=-5
3. Vi>=5
Relevant Equations
V=IR
Assume constant voltage drop model
15826528330785185152945627534342.jpg
 
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Flying_Dutchman said:
I was trying to obtain a graph between the input and output voltage .

For the first case when input voltage vis between +5 and -5 volt I obtained the input voltage same as output voltage since the diodes will be reverse biased .

I just couldn't find the relation between these voltages when input voltage is below -5 V and above +5
So far so good.

When the input goes above +5 V, what happens to the diodes? Which one changes?
The diodes that are cut off (reversed bias) can be ignored as open cct. So draw what's left and see what you think will happen.

You need to show what you're doing and people will comment.
 
15826590146257995968003440983700.jpg

When input is above 5V only this branch conducts because the diode will be forward biased . I tried using Kirchoffs voltage law to find the relation between input output voltages but for that i need current that is not given.
 
You could write a formula for the current in terms of Vi.
Then use that current to get a fromula for the output

Or an intuitive way is to ask, first, what if the battery and diode were shorted: what would Vout be then?
And if you put the battery back in, what difference does that make?
Then just add in the diode as well.

Edit: Maybe stick to the algebra! My intuition wasn't as good as I thought!
 
Last edited:

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