Transforming to a Normal Form (PDE)

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Homework Help Overview

The discussion revolves around solving a partial differential equation (PDE) for the function u(x,y) and transforming it into a normal form. Participants are exploring the implications of the equation u_{ww}=0 and its integration.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the form of the solution to the PDE, questioning the nature of the function B(v) and the constants involved. There is a focus on the interpretation of the indefinite integral of zero and its implications for the solution.

Discussion Status

The discussion is active, with participants providing insights into the form of the solution and clarifying the role of arbitrary functions versus constants. There is an acknowledgment of the need to consider A as a function of v, indicating a productive exploration of the problem.

Contextual Notes

Participants are navigating the specifics of the PDE and its transformation, with some uncertainty about the definitions and assumptions regarding the functions involved.

lema21
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Homework Statement
Find the type, transform to normal form and solve. Show your work in detail: Uxx+2Uxy+Uyy=0
Relevant Equations
Hyperbolic- AC-B^2<0
Parabolic- AC-B^2=0
Elliptic- AC-B^2>0
I don't know how to solve for u(x,y) from where I left of after 5.

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Shouldn't you be getting: ##u_{ww}=0##, i.e. ##u(w,v)=Aw+B(v)## where ##B(v)## is a function of ##v## and ##A## is a constant?
 
MathematicalPhysicist said:
Shouldn't you be getting: ##u_{ww}=0##, i.e. ##u(w,v)=Aw+B(v)## where ##B(v)## is a function of ##v## and ##A## is a constant?

The indefinite integral of 0 with respect to w is an arbitrary function of v, not an arbitrary ocnstant.
 
pasmith said:
The indefinite integral of 0 with respect to w is an arbitrary function of v, not an arbitrary ocnstant.
yes correct then A should be A(v).
 

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