Transition of Calcium Hydrogen-like Ion

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SUMMARY

The transition of a hydrogen-like calcium ion emitting a photon with energy E = 756 eV corresponds to a transition from n=3 to n'=2. The relevant energy equation used is E=Z^2*E_R*(1/n^2-1/n'^2), where Z=20 for calcium and E_R is the Rydberg energy of 13.6 eV. Initial assumptions led to incorrect values for n', but through iterative calculations, the correct transition was identified. The discussion emphasizes the importance of correctly interpreting the quantum states involved in the transition.

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Homework Statement



A hydrogen‑like ion of calcium emits a photon with energy E = 756 eV. What transition was involved?

Homework Equations



The energy equation: E=Z^2*E_R*(1/n^2-1/n'^2)

The Attempt at a Solution



First, Z=20 for a calcium ion, and E_R is the Rydberg energy 13.6 eV. Then I plugged everything in assuming that the electron which emits the photon goes back to the ground state, i.e. n=1.

However, I get n' ≈ 1.07, which does not seem sensible to me.

Any ideas or suggestions, please? Much appreciated.

Note: How do you write down the equations in a neat format on the forums? I'm a newbie so please go easy on me!
 
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If your result is wrong, one of the assumptions is wrong. In this case, the electron does not go back to the ground state.

Formula formatting -> LaTeX
 
mfb said:
If your result is wrong, one of the assumptions is wrong. In this case, the electron does not go back to the ground state.

Formula formatting -> LaTeX

Thank you for the formula formatting guidelines!

In that case, how do I deduce the transition involved? Because otherwise the problem doesn't state much, unless I'm missing another given assumption.
 
Attempt at the problem

Ok so I separated the transition term of the equation ##E=Z^2E_R(\frac{1}{n^2}-\frac{1}{n'^2})##: $$\frac{E}{Z^2E_R}=\frac{1}{n^2}-\frac{1}{n'^2}$$

and knowing that the right hand side's value, I started plugging in values for n for which $$\frac{1}{n'^2}= \frac{1}{n^2}-\frac{E}{Z^2E_R}$$ will still be come out positive.

I tried for a transition back to the n=2 state and got a close approximation to an integer value n'=9.

Could someone please check this for me?
 
Did you consider the square for n'?
I get a different result with smaller numbers.
 
I did.

If I consider a transition back to the ground state, I get n' to be some non-integer close to 1, which does not make sense.

mfb said:
Did you consider the square for n'?
I get a different result with smaller numbers.

What was your result?
 
n=2 is right, it fits perfectly to n'=3 and not to 9.
 
mfb said:
n=2 is right, it fits perfectly to n'=3 and not to 9.

Yes, you are right about that! That was my mistake.

The transition is from n=3 to n'=2. Guess for this problem they wanted you make a reasonable guess.
 

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