Translational and rotational kinetic energy-Mass Unknown

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SUMMARY

The discussion focuses on calculating the mass of a liquid inside a hollow, thin-walled sphere with a known mass of 20 kg, rolling down a 30° incline. The moment of inertia for the sphere is given as ICM = 2MR²/3. The sphere rolls 20 meters in 3.6 seconds, allowing for the determination of acceleration and subsequently the mass of the liquid. Participants emphasize that the translational speed of rolling spheres is independent of mass and radius, and suggest using the provided moment of inertia to solve for the unknown mass.

PREREQUISITES
  • Understanding of translational and rotational kinetic energy
  • Knowledge of moment of inertia, specifically ICM = 2MR²/3
  • Familiarity with the physics of rolling motion
  • Basic principles of acceleration and motion on inclined planes
NEXT STEPS
  • Calculate the acceleration of the sphere using kinematic equations
  • Determine the translational speed (v-cm) of the sphere at the bottom of the incline
  • Apply Newton's second law to relate forces acting on the sphere to find the mass of the liquid
  • Explore the differences in motion between solid and hollow spheres in rolling scenarios
USEFUL FOR

Physics students, educators, and anyone interested in understanding the dynamics of rolling objects and the application of kinetic energy principles in real-world scenarios.

Crusader711
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A hollow, thin-walled sphere (ICM = 2MR2/3) of mass 20 kg is completely filled with a liquid of unknown mass. The sphere is released at the top of a plane inclined at 30° to the horizontal, and it rolls 20 m to the bottom in 3.6 s. What is the mass of the liquid?



2.My approach is translational and rotational kinetic energy, first off. I know that for rolling spheres the v-cm is not dependent upon the mass nor radius of the objects. So I come up with a translational speed but I'm not certain where to go from there. But the problem wants the mass of the liquid. I have two different sphere's in theory, a solid and a thin-walled version.



3. Looking for a lead into the next step...
 
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Hi Crusader711! :smile:
Crusader711 said:
I know that for rolling spheres the v-cm is not dependent upon the mass nor radius of the objects.

for a particular shape, yes
I have two different sphere's in theory, a solid and a thin-walled version.

But you're given the moment of inertia anyway.

Since we're not told the radius of the sphere, I think we're supposed to assume that the liquid does not rotate.

So find the acceleration, call the mass of the liquid "m", and carry on from there. :smile:
 
Rolling verses Frictionless

Would we treat the spheres differently?

thin-walled sphere rolling...

...then solid sphere with liquid, liquid sphere moving down incline (not rolling), but we have to account for the ICM of the thin-walled shell too?

Any thoughts?
 
(just got up :zzz:)

i assume "ICM" means moment of inertia?

you are given the moment of inertia and the mass, why do you need to know anything else?
 

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