Translational Speed of Cylinder on Inclined Plane: Find the Answer

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SUMMARY

The discussion focuses on calculating the translational speed of a solid cylinder with a mass of 1.12 kg and a radius of 0.017 m as it rolls down a 77.7° incline from a height of 3.40 m. Utilizing the work-energy principle, the potential energy lost (P.E. = mgh) is equated to the kinetic energy gained (K.E. = 1/2 mv² + 1/2 Iω²). The moment of inertia for the cylinder is I = 1/2 mr², and the relationship between linear velocity and angular velocity is given by v = rω. The final speed can be determined by solving these equations with the acceleration due to gravity set at 9.81 m/s².

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Homework Statement


A solid cylinder with a mass of 1.12 kg and a radius of 0.017 m starts from rest at a height
of 3.40 m and rolls down a 77.7◦ slope. What is the translational speed of the cylin-
der when it leaves the incline? The acceleration of gravity is 9.81 m/s2 . Answer in units
of m/s.

Homework Equations


I have angular speed which is
v=r\omega

we know r (.017m). But I'm having trouble finding the others.
Any help would be great. Thanks.
 
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