- #1
yosimba2000
- 206
- 9
The voltage value on a wire a distance away from the signal-port (where we apply the initial voltage) has a phase delay because the current takes time to travel down the wire.
But how do you visualize this? First we have a voltage at the beginning, and that causes current to flow. Then a distance later, the current causes a different voltage at wherever the current is? Voltage is energy per charge, so does that mean the voltage is being "carried" by the current, and the voltage propagation delay is caused by how long it takes for the current to move?
So in the context of a charge in a uniform electric field within a vacuum:
1) Charge moves with electric field
2) E-field is force per charge, so multiply by the distance moved to get energy per charge, AKA voltage
3) This voltage is now stored within the charge? So because the charge takes time to move a distance, this results in voltage propagation delay?
But how do you visualize this? First we have a voltage at the beginning, and that causes current to flow. Then a distance later, the current causes a different voltage at wherever the current is? Voltage is energy per charge, so does that mean the voltage is being "carried" by the current, and the voltage propagation delay is caused by how long it takes for the current to move?
So in the context of a charge in a uniform electric field within a vacuum:
1) Charge moves with electric field
2) E-field is force per charge, so multiply by the distance moved to get energy per charge, AKA voltage
3) This voltage is now stored within the charge? So because the charge takes time to move a distance, this results in voltage propagation delay?