Transmission lines & reflections

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SUMMARY

This discussion focuses on analyzing voltage reflections in a lossless coaxial cable with a relative permittivity (εr) of 3, driven by a pulse source with an internal impedance of 10 ohms and a square wave pulse of 1 V amplitude. The characteristic impedance (Zc) of the cable is calculated to be 50 ohms, with a one-way time delay of 58 ns. The voltage at the end of the line will initially reach 5/6 V, lasting until 108 ns, followed by a negative pulse of -5/6 V until 158 ns. The outcome of reflections depends on the termination of the line, which must be clarified for accurate analysis.

PREREQUISITES
  • Understanding of coaxial cable properties and characteristics
  • Knowledge of pulse signal behavior and square waveforms
  • Familiarity with characteristic impedance calculations
  • Concept of voltage reflections in transmission lines
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  • Learn about the effects of impedance mismatches on voltage reflections
  • Explore the use of simulation tools like LTspice for visualizing transmission line behavior
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Electrical engineers, telecommunications professionals, and students studying transmission line theory and signal integrity in data networks.

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Homework Statement



[/B]
Can someone help me solving this problem ?
A lossless coaxial cable is used in a data network. it has an er =3 (relative permittivity) It is driven by a pulse
source with internal impedance of 10 ohm, 1 V amplitude, square wave with
duration of both positive and negative pulse 50 ns, with negligible rise and
fall-time. Sketch the voltage at the end of the line as function of time for 300 ns

Homework Equations

The Attempt at a Solution


The Zc = 50 ohms from caluclutation. The one way time delay due to the cable length is 58 ns. At start a voltage of 5/6V positive will propagte to the end it will be there after 58 ns and it will last till 108 ns. after that the negative pulse of -5/6 V will reach the end on 108 ns and will last till 158 ns. I have no idea how it will be with reflections?
 
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I think you are assuming that the line is terminated with it's characteristic impedance of 50 ohm.
The characteristic impedance of the line is the voltage to current ratio of the traveling wave.
If the line is open-circuit or short-circuit there will be either zero current or zero voltage at the end.
 
+1 You need to know how it's terminated (or make an assumption about how it's terminated from the question).
 

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