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i know that

=VQ/(Ib)τ

now im looking for the maximum stress so i will find that at the point at the centre of the rectangle

Q=A*[tex]\bar{y}[/tex]

A=0.5*d*b

[tex]\bar{y}[/tex]=0.25*d

===> Q=0.125d^{2}b

I=(b*d^{3})/12

=VQ/(Ib)τ

=V*0.125dτ^{2}b*12/((b^{2}*d^{3})

=1.5V/(bd)τ

now d changes as a function of X

i know thatis constant from x=0 to x=Lτ

but V is constant throughout and so is b, so how can this be?

i tried making a differential equation where i know d(0)=do and d(L)=0 using d/dx=0 but really didnt manageτ

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# Homework Help: Transverse loading with varing cross section

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