λ∂1. The problem statement, all variables and given/known data Aguitar string lies along the x-axis when in equilibrium. The end of the string at x=0 (the bridge of the guitar) is fixed. A sinusoidal wave with amplitude A=0.750 mm and frequency f =440 Hz, corresponding to the red curves in Fig. 15.24, travels along the string in the -x-direction at 143m/s. It is reflected from the fixed end, and the superposition of the incident and reflected waves forms a standing wave. (a) Find the equation giving the displacement of a point on the string as a function of position and time. (b) Locate the nodes. (c) Find the amplitude of the standing wave and the maximum transverse velocity and acceleration. 2. Relevant equations ∂y(x,t)/∂t=AswSin(kx)Cos(wt)w T=1/f λ=v/f position of a node=λ/2 3. The attempt at a solution So, I get how to do everything up until part c. The partial derivative of the transverse wave with respect to time and holding x constant is: ∂y(x,t)/∂t=(4.15/m/s)sin[(19.3 rad/m)x]cos[(2760rad/sec)t Now, by just looking at this function, I could tell that the maximum velocity is 4.15. The function will oscillate between +4.15 and -4.15. Well, I thought that if I find the position of a node and the time at which it will occur, this function would yield to an answer of 4.15m/s. The values I used for the period is .002sec so, a node will happen at half a period which is .001sec. One wavelength is .325m and a node will happen half way through. This means that a node will occur at x=.1625m. When I plug in the values in the above equation I get -.020599061m/s which is not the correct an answer. Would you please let me know if I am thinking about this incorrectly? Doesn't maximum velocity happen at the intersection point with the x-axis? Isn't this point a node in this case? This is an example in a textbook and I am trying to figure the maximum velocity by not just looking at the amplitude of the function.