Triangle inscribed within a circle

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In a triangle ABC inscribed in a circle with diameter AC, the angle BCA can be determined using the properties of inscribed angles. Given that arc BC subtends an angle of 40 degrees, angle BCA measures 20 degrees, as inscribed angles are half the measure of the subtended arc. Additionally, since AC is the diameter, angle ABC is a right angle, measuring 90 degrees. This leads to angle CAB being 70 degrees, completing the triangle's angle measures. Understanding these relationships is crucial for solving problems involving inscribed angles in circles.
BrownianMan
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ABC inscribed within a circle whose diameter AC forms one of the sides of hte triangle. If Arc BC on the circle subtends an angle of 40 ddegrees, find the measure of angle BCA within the triangle
 
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What's your idea ?
Any drawing ?
 
I haven't done this kind of thing since high school. Could you explain how you measure inscribed angles? My initial guess is that one of the sides is 90, one 40, and the other must be 50...
 
Yes that's right. Because whenever you have a triangle with one of its sides being the diameter of the circle, then the opposite angle to that side will be 90o.
 
If angle A has its vertex on a circle and subtends an arc of \theta degrees, then the measure of the angle is \theta/2 degrees. You are given that one angle of the triangle subtends an arc of 40 degrees and another an arc of 90 degrees.
 

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