An isosceles-triangle-shaped ladder like the picture above, has a negligible mass. A man with mass m kg climb the ladder till the height is 3 meter (see picture above).
Determine the tension of the link (at horizontal position in the picture) between the sides of ladder.
ΣF = 0
Στ = 0 (τ is moment)[/B]
The Attempt at a Solution
I've drawn the free body diagram
I didn't draw the gravitational force of the ladder since the ladder mass is negligible.
∑Fx = 0
N4 = N3
N1+N2+Nman - Wman = 0
Then I don't know what to do.. Please help me
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