How Do You Calculate Net Resistance in a Triangular Network?

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To calculate net resistance in a triangular network, one must consider both series and parallel resistor configurations. The equations for equivalent resistance (Req) in series and parallel must be applied correctly to find the net resistance between points a and c, and a and b. The assumption that R = R' simplifies calculations, but the presence of multiple paths complicates the analysis. When R' is set to 2.5R, the net resistance between points a and b changes, requiring a reevaluation of the circuit configuration. Clear documentation of attempted solutions is crucial for effective assistance in solving these types of problems.
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Homework Statement


Assuming R = R' in the network shown above, determine the net resistance between the points a and c. Express your answer as a number times R.
b. Assuming R = R', determine the net resistance between the points a and b.
c. Now suppose R' = 2.5R, and find the net resistance between points a and b.
P26_36.jpg

Homework Equations


Req=R1+R2+R3
For resistors in series

1/Req= 1/R1+1/R2+1/R3
For resistors in parallel

The Attempt at a Solution


I tried to redraw the circuit, but I'm not sure I did it right. Also, I would think that the resistance would just be R because there is only one resistor from a to c, but that seems too easy. Any help would be appreciated.
 
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The answer is not R as there is certainly more than one path from a to c. You really should show at least some of your attempt(s) even if they didn't pan out, and not just say that you tried this or that. We need to see how you've approached the problem in order to know how best to help.

See the thread: Combining Resistors
 

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