Tricky Differentiation of Derivative

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SUMMARY

The discussion centers on deriving the governing equation for conservation of momentum in non-Newtonian fluids, specifically focusing on the differentiation of the expression d/dx(((-dv/dx)^(m-1))*(dv/dx)). The correct approach involves recognizing that this can be simplified to d/dx{(dv/dx)^m}, which results in m(dv/dx)^(m-1)(d²v/dx²). The use of the chain rule and product rule is essential in this differentiation process, clarifying the mathematical steps often overlooked in derivations.

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  • Understanding of calculus, specifically differentiation techniques.
  • Familiarity with non-Newtonian fluid mechanics.
  • Knowledge of chain rule and product rule in calculus.
  • Basic concepts of conservation of momentum in fluid dynamics.
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olechka722
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I am having trouble remembering the correct approach here. This is in regards to deriving a governing equation for conservation of momentum for a non-Newtonian fluid. I thought about posting in engineering, but it is more of a calculus question:

d/dx(((-dv/dx)^(m-1))*(dv/dx)) where we are differentiating with respect to x, v is a function of x, and m is some value, not necessarily in integer.

I thought about treating dv/dx as f(x) and doing the chain rule and then the product rule, but am unsure. This step is skipped in the derivation I am looking at, and I would love to figure out the math behind it. Thanks!
 
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Hi olechka722! :smile:

If you mean d/dx{(dv/dx)m-1(dv/dx)},

that's just d/dx{(dv/dx)m},

= m(dv/dx)m-1d2v/dx2
 

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