- #1
arizona_cards_11
- 17
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Trig Functions...
I don't really understand how my book wants me to approach this problem. And I know that you appreciate work...because this is for my benefit after all...but how exactly would this be worked?
Direction: Solve the equation for (theta)... 0 is less than or equal to (theta) < 2*pi
2sin^2(theta) = 1
The answers in the back of the book given in radians:
(theta) = (pi/4) , ((3*pi)/(4)) , ((5*pi)/(4)) , ((7*pi)/(4))
I don't really understand how my book wants me to approach this problem. And I know that you appreciate work...because this is for my benefit after all...but how exactly would this be worked?
Direction: Solve the equation for (theta)... 0 is less than or equal to (theta) < 2*pi
2sin^2(theta) = 1
The answers in the back of the book given in radians:
(theta) = (pi/4) , ((3*pi)/(4)) , ((5*pi)/(4)) , ((7*pi)/(4))