Trig identity in complex multiplication

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Shaybay92
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Just wondering how this is simplified to the third line:

If w, z are complex numbers

wz = rs( cos[tex]\alpha[/tex] + isin [tex]\alpha[/tex] ) (cos [tex]\varphi[/tex] + isin [tex]\varphi[/tex])

wz = rs(cos[tex]\alpha[/tex] cos [tex]\varphi[/tex] - sin [tex]\alpha[/tex]sin[tex]\varphi[/tex]) + i(sin [tex]\alpha[/tex]cos[tex]\varphi[/tex] + cos [tex]\alpha[/tex] sin [tex]\varphi[/tex]))

wz = rs(cos ([tex]\alpha[/tex] +[tex]\varphi[/tex]) + i sin([tex]\alpha[/tex] +[tex]\varphi[/tex]))

What sort of trigonometric identity is used here between the 2nd and 3rd lines?
 
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Exactly those as written:

sin(a+b) = sin(a)cos(b) + cos(a)sin(b)
cos(a+b) = cos(a)cos(b) - sin(a)sin(b)
 
Thanks I hadn't seen these identities before
 
You would think so but apparently my school doesn't see the importance in teaching this stuff. The only identity we were taught was

sin^2(x) + cos^2(x) = 1

not even all the half angle ones which I'm finding out about now... How helpful for me!