Trig proof with two angles and many functions

AI Thread Summary
The discussion revolves around proving the trigonometric identity cotA cotB = (cscB + cotA) / (tanA secB + tanB). A participant expresses difficulty in solving the problem despite using Pythagorean identities and other methods. They receive advice to start from the right side of the equation and convert all terms into sines and cosines, leading to a complex fraction. The suggested approach involves simplifying the fractions in both the numerator and denominator. Ultimately, the participant successfully solves the problem after following this guidance.
stevensen
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Homework Statement


Prove:
cotAcotB=(cscB+cotA)/(tanAsecB+tanB)


Homework Equations


cotx=1/tanx, etc.
I tried using pythagorean identities, like 1+cot2x=csc2x, and others, but I've been unable to solve the problem.


The Attempt at a Solution


Please help me out. The examples in my textbook don't seem very useful here. I've tried everything I could think of.
 
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You need to show some work, but here's a big hint. Start from the right side. Convert everything in terms of sines and cosines. You'll have a complex fraction. Add the two fractions in the numerator, and then add the two fractions in the denominator. Take it from here.
 
Thanks. I finally figured it out.
 
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