Trig work problem (am I correct?)

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Miike012
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Trig work problem... (am I correct?)

Homework Statement


If we call the height @ which the supports cross ,x, express this height as an equation in terms of H1 and H2 Only... Use similar triangle...

Are my proportion correct?
x/H1 = (L1-L)/L1
x/H2 = (L)/L1 = (L1-L)/L1

Because Where the two lines intersect you can see that the two angles are congruent (If I did it correctly)
Thus L1-L = L


And Are my congruent angles in my picture correct?


Homework Equations





The Attempt at a Solution

 

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Miike012 said:
Because Where the two lines intersect you can see that the two angles are congruent (If I did it correctly)
Thus L1-L = L

(try using the X2 icon just above the Reply box :wink:)

No, that's obviously not correct … you're saying L is always half of L1, which it isn't. :redface:
Are my proportion correct?
x/H1 = (L1-L)/L1
x/H2 = (L)/L1 = (L1-L)/L1

Correct :smile:, but it'll be easier if you rewrite it …

x/H1 = 1 - L/L1
x/H2 = L/L1

carry on from there :wink:
 


tiny-tim said:
(try using the X2 icon just above the Reply box :wink:)

No, that's obviously not correct … you're saying L is always half of L1, which it isn't. :redface:Correct :smile:, but it'll be easier if you rewrite it …

x/H1 = 1 - L/L1
x/H2 = L/L1

carry on from there :wink:


The segment starting from the right starting @ H2 going towards line x has to be the same length as the line segment L1 to x... because isn't line x is a angle bisector...

Thus segment L1-L must equal segment L...?
 


I see what you are saying but I guess I am confused.. I am just learning geometry so maybe you can help my understand because it states that if an ray bisects an angle.. the ray creates two congruent angles... and a point on the angle bisector is equal distance from the sides of the angle...
 


So my angles that I say are equal are incorrect?
If you can.. can u show me which ones are equal?