Trigonometric derivative: power rule + product rule

\frac{dy}{dx} = -2(\cos{x}\sin{2x})^{-3}[\sin{2x}(-\sin{x}) + \cos{x}(2\cos{2x})] \frac{dy}{dx} = -2(\cos{x}\sin{2x})^{-3}[-\sin{x}\sin{2x} + 2\cos{x}\cos{2x}] \frac{dy}{dx} = -2(\cos{x}\sin{2x})^{-3}[-\sin{x}\sin{2x} + 2(\cos{x}\cos{2x} + \sin{x}\sin{2x})] \
  • #1
cinematic
8
0

Homework Statement


Derive the following:

y = (cosxsin2x)-2


2. The attempt at a solution

Basically I saw this as a power rule with two products in the middle.

So y = -2 (cos2cos2x-sinxsin2x)-1

But the correct answer is completely different, it's:

4(3sin2x - 1) all over
cos2xsin32x

Could someone please go through the steps to get to the correct solution? Thanks in advance!
 
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  • #2
cinematic said:

Homework Statement


Derive the following:

y = (cosxsin2x)-22. The attempt at a solution

Basically I saw this as a power rule with two products in the middle.

So y = -2 (cos2cos2x-sinxsin2x)-1

But the correct answer is completely different, it's:

4(3sin2x - 1) all over
cos2xsin32x

Could someone please go through the steps to get to the correct solution? Thanks in advance!

[tex] y = (cos{x}sin{2x})^{-2} [/tex]

[tex] \frac{dy}{dx} = -2(\cos{x}\sin{2x})^{-3}[\underbrace{\frac{d}{dx}(\cos{x}\sin{2x})}_{use\: product \:rule}] [/tex]
 
Last edited:

What is the trigonometric derivative?

The trigonometric derivative is a mathematical tool used to calculate the rate of change of trigonometric functions. It is based on the chain rule and involves finding the derivative of the inner function and multiplying it by the derivative of the outer function.

What is the power rule for trigonometric derivatives?

The power rule for trigonometric derivatives states that the derivative of a trigonometric function raised to a power is equal to the power multiplied by the derivative of the trigonometric function.

How do you use the product rule for trigonometric derivatives?

The product rule for trigonometric derivatives states that the derivative of the product of two trigonometric functions is equal to the first function multiplied by the derivative of the second function plus the second function multiplied by the derivative of the first function.

What is the general formula for finding the derivative of a trigonometric function?

The general formula for finding the derivative of a trigonometric function is: f'(x) = g'(x) * h(x) + g(x) * h'(x), where g(x) and h(x) are the two trigonometric functions being multiplied together.

Can the trigonometric derivative be used to find the rate of change of any trigonometric function?

Yes, the trigonometric derivative can be used to find the rate of change of any trigonometric function, as long as the function follows the rules of the power and product rules for derivatives.

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