1. The problem statement, all variables and given/known data Solve: 5sin(x) + (2 * squrroot 3) = (squarroot 3) + 3sin(x) 2. Relevant equations sin (60) = square root 3 / 2 C.A.S.T. rule 3. The attempt at a solution 5sin(x) + (2 * squrroot 3) = (squarroot 3) + 3sin(x) 5sin(x) - 3sin(x) = (squarroot 3) - (2 * squrroot 3) 2sin(x) = - (squarroot 3) sin(x) = - (squarroot 3) / 2 Now....sin(x) = - (squarroot 3) / 2 is 60 degrees by reference angle. However, because the sign was in a negative we must select the quadrants in which sine is negative. Those are the third and fourth quadrants. This means that the degrees will be 300 degrees and 240 degrees. However, the answer in my course material says the answers are 60 degrees and 120 degrees. But these are in quadrants in which the sine is positive...and as we saw in that equation, the sine is negative. Am I misreading something? Thanks all in advance.