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Trigonometric functions and the unit circle

  1. Feb 16, 2009 #1
    1. The problem statement, all variables and given/known data
    Hi all.

    Today I had to solve: [itex]\cos \theta = -1/2[/itex]. What I did was to look in a table to find that [itex]\theta = 2\pi/3 \quad \text{and}\quad \theta = 4\pi/3[/itex].

    My question is what is the general strategy when I wish to write this as a a function of an integer n? Is there even a general strategy for this?

    Thanks in advance.
     
  2. jcsd
  3. Feb 16, 2009 #2

    CompuChip

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    What do you mean?
    Can you solve
    [tex]\cos\theta = n[/tex]
    without looking it up (no, unless you have a calculator), or can you write the solutions
    [tex]\theta = 2\pi/3, 4 \pi / 3 [/tex]
    as
    [tex]\theta = \frac{2\pi}{3} + 2 \pi n, \frac{4 \pi}{3} + 2 \pi n[/tex]
    or can you combine those into one formula (no, not particularly nicely).
     
  4. Feb 16, 2009 #3
    What I meant was your #2 suggestion: If there is any way to write the two solutions nicely for all n.

    Hmm, ok then. I will just stick to writing the solutions as you did. Thanks.
     
  5. Feb 16, 2009 #4

    CompuChip

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    OK, so maybe you can write something like
    [tex]\frac{2 \epsilon \pi}{3} + 2 \pi n[/tex]
    with [itex]n \in \mathbb{Z}, \epsilon = 1, 2[/itex]
    or
    [tex]\frac{k \pi}{3}[/tex]
    with [itex]k \in \mathbb{Z}, k \equiv 2 \text{ or } 4 \, \operatorname{mod} 7[/itex].

    But I think the expression from my earlier post is more common (in any case, you only need to think about it half as long to understand what it's saying and where it comes from :smile:).
     
  6. Feb 16, 2009 #5
    Ok, thanks!
     
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