Trigonometric Half Angle Formula Explained and Applied

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SUMMARY

The discussion focuses on the application of the tangent half-angle formula to solve the expression tan[1/2 arcsin(-7/25)]. The user initially struggles with the half-angle concept but ultimately derives the correct answer of -1/7 after several iterations and corrections. Key steps include recognizing the need to rationalize the denominator and verifying results with a calculator for accuracy. The final solution emphasizes the importance of checking calculations in trigonometric problems.

PREREQUISITES
  • Understanding of trigonometric functions, specifically sine and tangent.
  • Familiarity with the half-angle formulas in trigonometry.
  • Ability to rationalize denominators in mathematical expressions.
  • Basic calculator skills for verifying trigonometric calculations.
NEXT STEPS
  • Study the derivation and applications of the tangent half-angle formula.
  • Practice solving trigonometric identities involving arcsin and arctan.
  • Learn about rationalizing denominators in various mathematical contexts.
  • Explore numerical methods for verifying trigonometric solutions using calculators.
USEFUL FOR

Students studying trigonometry, educators teaching trigonometric identities, and anyone looking to improve their problem-solving skills in trigonometric equations.

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Homework Statement



\tan[\frac{1}{2} \arcsin(\frac{-7}{25})]

The Attempt at a Solution



I'm not sure how to take 1/2 the arcsin, should this use the half-angle formula?

Normally I would draw a triangle using the sin value (-7/25), then find the tan value (24/25), but the 1/2 is throwing me off.

How do I start this? Is this 1/2 the sin value (-7/25)= -7/50, then solve for the tan(-7/50)?
 
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Use the tangent half angle formula. tan(x/2)=??
 
Thanks, so i get

-\sqrt{26}

Does that sound right?
 
jrjack said:
Thanks, so i get

-\sqrt{26}

Does that sound right?

arcsin(-7/25) is about -0.3. If you take half of that and take the tangent, it's nowhere near -sqrt(26) which is about -5. Is it? You can check these solutions using rough estimates or a calculator.
 
-\sqrt{\frac{1+\cos x}{1-\cos x}}
-\sqrt{\frac{1+\frac{24}{25}}{1-\frac{24}{25}}}
=-\sqrt{26}
 
jrjack said:
-\sqrt{\frac{1+\cos x}{1-\cos x}}
-\sqrt{\frac{1+\frac{24}{25}}{1-\frac{24}{25}}}
=-\sqrt{26}

tan(0/2)=0. If you put x=0 into your supposed half angle formula, what do you get? Does it work?
 
Sorry, I now realize I have my signs flipped in my formula.
I think my answer should be:-\sqrt{\frac{1}{26}}
 
jrjack said:
Sorry, I now realize I have my signs flipped in my formula.
I think my answer should be:-\sqrt{\frac{1}{26}}

That doesn't work either because (1-24/25)/(1+24/25) isn't equal to 1/26. Now what's it really equal to??
 
Sorry, I got in a hurry, between typing the tex and working the problem several different ways (wrong of course).

It should equal 1/49, which means my answer should be -\sqrt{\frac{1}{49}}
 
  • #10
jrjack said:
Sorry, I got in a hurry, between typing the tex and working the problem several different ways (wrong of course).

It should equal 1/49, which means my answer should be -\sqrt{\frac{1}{49}}

Ok, aside from the fact there is a simpler way to write -1/sqrt(49) could you try and check that using a calculator from your original expression? It's really useful to have a simple way of self-checking whether you are way off or not.
 
  • #11
Thank you for your help.
I realize I still need to rationalize the denominator, and after checking with my calculator both answers come out to -.142857, so that must be correct.

My final answer should be -1/7

Once again, thank you for your help.
 
  • #12
jrjack said:
Thank you for your help.
I realize I still need to rationalize the denominator, and after checking with my calculator both answers come out to -.142857, so that must be correct.

My final answer should be -1/7

Once again, thank you for your help.

Very welcome and quite right. The main lesson is how easy these answers are to check with a calculator.
 

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