Trigonometric identities and complex numbers

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SUMMARY

The discussion focuses on proving the identity sin(x) + cos(x) = (√2)cos(x - π/4) using complex numbers. Key equations include cos(x) = (e^(ix) + e^(-ix))/2 and sin(x) = (e^(ix) - e^(-ix))/2i. The solution involves expressing the right side in exponential form and simplifying it to match the left side. Participants emphasize the importance of recognizing the relationship between trigonometric functions and complex exponentials.

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  • Understanding of complex numbers and Euler's formula
  • Familiarity with trigonometric identities
  • Knowledge of exponential functions in mathematics
  • Ability to manipulate algebraic expressions
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  • Study Euler's formula and its applications in trigonometry
  • Learn how to derive trigonometric identities from complex exponentials
  • Practice converting trigonometric expressions into exponential form
  • Explore advanced topics in complex analysis related to trigonometric functions
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Students studying mathematics, particularly those focusing on trigonometry and complex numbers, as well as educators seeking to enhance their teaching methods in these areas.

PedroB
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Homework Statement



Show, using complex numbers, that sin(x)+cos(x)=(√2)cos(x-∏/4)

Homework Equations



cos(x)=(e^(ix)+e^(-ix))/2
sin(x)=(e^(ix)-e^(-ix))/2i

e^ix=cos(x)+isin(x)

The Attempt at a Solution



I was given the hint that sin(x)=Re(-ie^(ix)), but have thus far not been able to determine its usefullness. I have tried squaring the expression, which (after simplification) yields:

1+sin(2x)

but cannot seem to go further. I assume that the crux of the solution lies in fully expressing sin(x)+cos(x) as purely cos in terms of complex exponentials, but everything I try just brings me back to the original expression. Am I missing a fundamental equivalence between either of these trigonometric functions and a complex number? Any help would be greatly appreciated, thank-you in advance.

(Obviously all work done in trying to solve this problem involves the assumption that I do not know the final answer)
 
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PedroB said:

Homework Statement



Show, using complex numbers, that sin(x)+cos(x)=(√2)cos(x-∏/4)

Homework Equations



cos(x)=(e^(ix)+e^(-ix))/2
sin(x)=(e^(ix)-e^(-ix))/2i

e^ix=cos(x)+isin(x)

The Attempt at a Solution



I was given the hint that sin(x)=Re(-ie^(ix)), but have thus far not been able to determine its usefullness. I have tried squaring the expression, which (after simplification) yields:

1+sin(2x)

but cannot seem to go further. I assume that the crux of the solution lies in fully expressing sin(x)+cos(x) as purely cos in terms of complex exponentials, but everything I try just brings me back to the original expression. Am I missing a fundamental equivalence between either of these trigonometric functions and a complex number? Any help would be greatly appreciated, thank-you in advance.

(Obviously all work done in trying to solve this problem involves the assumption that I do not know the final answer)

In addition to your hint, another identity is cosx = Re(eix).

Start with the right side of your identity, √2 cos(x - ##\pi/4##). The identity I show just above can be used to rewrite √2 cos(x - ##\pi/4##) in its exponential form. The rest is fairly straightforward but does take a few steps.
 

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