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Trigonometric identity forced oscillations

  1. Apr 22, 2007 #1
  2. jcsd
  3. Apr 22, 2007 #2

    cristo

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    Well, you've got an expression that's in the form sinAsinB; so you look to use the formula cos(A-B)=cosAcosB+sinAsinB.

    From this, you know that [tex]\cos\{\omega_it-\phi-\omega t\}=\cos\{\omega_i t-\phi\}\cos(\omega t)+\sin\{\omega_i t-\phi\}\sin(\omega t)[/tex]. You can work out the similar expression that [tex]\cos\{\omega_it-\phi+\omega t\}=\cos\{\omega_i t-\phi\}\cos(\omega t)-\sin\{\omega_i t-\phi\}\sin(\omega t)[/tex] Then subtract the second from the first.
     
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