- #1
Yankel
- 390
- 0
Hello all,
I am trying to solve the integral:
\[\int cot(x)\cdot csc^{2}(x)\cdot dx\]
If I use a substitution of u=cot(x), I get
\[-\frac{1}{2}cot^{2}(x)+C\]
which is the correct answer in the book, however, if I do this:
\[\int \frac{cos(x)}{sin^{3}(x)}dx\]
I get, using a substitution u=sin(x)
\[-\frac{1}{2}csc^{2}(x)+C\]
which according to MAPLE, is also correct. In addition, according to MAPLE the move I made for the new function, is also correct !
I am confused !
I am trying to solve the integral:
\[\int cot(x)\cdot csc^{2}(x)\cdot dx\]
If I use a substitution of u=cot(x), I get
\[-\frac{1}{2}cot^{2}(x)+C\]
which is the correct answer in the book, however, if I do this:
\[\int \frac{cos(x)}{sin^{3}(x)}dx\]
I get, using a substitution u=sin(x)
\[-\frac{1}{2}csc^{2}(x)+C\]
which according to MAPLE, is also correct. In addition, according to MAPLE the move I made for the new function, is also correct !
I am confused !