Trigonometry Identity problem I been trying to solve all day

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Homework Help Overview

The discussion revolves around solving the trigonometric equation 3cos(x) + 3 = 2 sin^2(x) within the interval 0 <= x < 2pi. Participants are exploring various approaches to manipulate and simplify the equation using trigonometric identities.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants attempt to rearrange the equation and express it in different forms, including factoring and moving terms around. There are discussions about recognizing standard forms and the implications of distribution versus factoring.

Discussion Status

Some participants have offered guidance on how to approach the equation by suggesting it be put into standard form. Others express confusion about their previous attempts and seek clarification on the steps taken. There is an ongoing exploration of the correct method to solve the equation.

Contextual Notes

Participants mention the challenge posed by an uninformative textbook, which may be contributing to their difficulties in understanding the problem and applying the relevant identities.

Juliano
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Homework Statement


solve 3cos(x) + 3 = 2 sin^2(x) where 0 <= x < 2pi

Homework Equations


The Attempt at a Solution


3(cos(x) + 1) = 2 sin^2(x)
3(cos(x) + 1) = 2 (1- cos^2(x))
I've tried this variation, and a couple others but it just does not pan out. Please help.

Oh yeah we have a real uninformative book.
 
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Juliano said:
3(cos(x) + 1) = 2 sin^2(x)
3(cos(x) + 1) = 2 (1- cos^2(x))
I've tried this variation, and a couple others but it just does not pan out. Please help.

Oh yeah we have a real uninformative book.
Don't factor out the 3 on the left side. Instead, distribute the right side, and move everything to the left side. After doing that, do you recognize the equation?


01
 
OK so I get the following
3 cos(x) + 3 = 2 - 2 cos^2(x)
3 cos(x) + 1 + 2 cos^2(x)=0
I tried this variation before, but I was unsure of what to do with the 1+2 cos^2(x) part. or maybe I'm just doing something wrong with the distribution and movement of the right side.
 
hold on I think I understand now.
(3 cos(x)+1)(2cos^2(x))= 0, the solve those two for 0
 
No no no, that's not right. It's best if you put the equation in "standard form" first, like this:
2cos^2(x) + 3 cos(x) + 1 = 0
Do you see what to do now?


01
 
wow. My head was so wrapped up in Identities I didn't even think to factor them in standard form
(cos +1)(2cos+1)=0
Thank you for shining a light through this fogged up brain of mine
 
Juliano said:
hold on I think I understand now.
(3 cos(x)+1)(2cos^2(x))= 0, the solve those two for 0
Althought the correct approach has already been pointed out, the equation above deserves a further comment. You can't get to the equation above from the one you showed in a previous post:
3 cos(x) + 1 + 2 cos^2(x)=0
If you multiply out your factored form, you get only two terms, not the three shown just above.
 
Yeah I see what you mean Mark44, Teachers always tell you to double check doing what you just did. Maybe I need to start doing that more.
 
Yeah, maybe you should, especially when you're in the early stages of learning something.
 

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