Triple integral, 2 parabolic cylinders

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SUMMARY

The discussion focuses on calculating the volume of a region bounded by the parabolic cylinders defined by the equations y=x² and x=y², along with the planes z=x+y and z=0. The correct setup for the triple integral is confirmed as ∫∫∫ dzdydx over the region R={(x,y,z) | 0 PREREQUISITES

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Homework Statement


Find the volume of the region which is bounded by the parabolic cylinders y=x², x=y² and z=x+y and z=0



Homework Equations





The Attempt at a Solution



I solved x=y² for y, and set that equal to y=x², and I got the intersection of the two parabolic cylinders to be at x=1. So I set it up as follows

∫∫∫ dzdydx R={(x,y,z)l 0<x<1,x²<y<sqrt(x), 0<Z<x+y}

(Preted my < are actually < and equal to signs)

I was wondering if someone could tell me if my set up is correct.

Thank you.
 
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Yes, that's exactly right.

By the way, "LaTex" is much nicer. On this board
[ tex ]\int_{z=0}^{x+y}\int_{y=x^2}^{\sqrt{x}}\int_{x= 0}^1 dxdydz [ /tex ]
gives (without the spaces inside [ ])
\int_{z=0}^{x+y}\int_{y=x^2}^{\sqrt{x}}\int_{x= 0}^1 dxdydz

Some other boards use "[math] [/math]" or "\( \)" or other things as delimiters but the codes are the same.
 
Ok I will try that next time. Thank you so much.
 

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