Triple Integral: Volume Between Y=1-X & Y=Z^2-1

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SUMMARY

The discussion focuses on calculating the volume between the surfaces defined by the equations Y = 1 - X and Y = Z^2 - 1 using triple integrals. The user expresses uncertainty regarding the boundaries of the region, noting that the given planes do not enclose a bounded volume. The key constraints identified are 0 < Y < 1 and 0 < X < √(1 - Y) for the first region, and -1 < Y < 0 and 0 < Z < √(1 + Y) for the second region. The conclusion emphasizes the need for clearer boundaries to properly set up the triple integral.

PREREQUISITES
  • Understanding of triple integrals in calculus
  • Familiarity with the equations of planes and parabolic cylinders
  • Knowledge of the Cartesian coordinate system
  • Basic skills in sketching 3D surfaces and regions
NEXT STEPS
  • Study the concept of bounded regions in multivariable calculus
  • Learn how to set up triple integrals for volume calculation
  • Explore the graphical representation of surfaces and their intersections
  • Review examples of volume calculations between different geometric shapes
USEFUL FOR

Students studying multivariable calculus, particularly those learning about triple integrals and volume calculations between surfaces. This discussion is also beneficial for educators seeking to clarify concepts related to bounded regions in three-dimensional space.

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Homework Statement


Volume between Y=1-X and Y = Z^2 -1

The Attempt at a Solution



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Sorry, not a good drawer.

0 < y < 1
0< x < SqRoot: 1-y

-1 < y < 0
0 < Z < Sqroot: 1 + y

I'm not even sure if this is right, we just started the triple integrals. Please Help.
 
Last edited by a moderator:
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The problem is that the plane y= 1- x and the parbolic cylinder [math]y= z^2- 1[/math] are not boundaries for a bounded region.
 
So there is not enough information?
 

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