- #1

crispy_nine

- 6

- 0

I have this one problem that seems unclear to me:

Show that the function f is continuous at (0,0) for

f(x,y) = ysin(1/x) if (x,y) do not equal (0,0)...and 0 if (x,y) = (0,0)

I'm thinking though, as with single variable calc, f is continuous at (a,b) provided that f(a,b) exists right? Therefore the top function is not continuous at (0,0), correct? But then again it states that x and y never do equal (0,0). I think I don't understand the question. Could somebody rephrase it or give me a hint? Cheers