Trouble with a line in Goldstein

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SUMMARY

The discussion centers on the integral presented in Goldstein's work, specifically equation 3.51, which involves the expression \(\int \frac{dx}{\sqrt{\gamma x^2 + \beta x + \alpha}}\). The integral's solution is debated, with a focus on the difference between the arcsin and arccos functions. The key conclusion is that the discrepancy arises from the constant of integration, where \(\frac{\pi}{2}\) can be absorbed, leading to the equivalence of \(\arccos(-x)\) and \(\arcsin(x)\) through their derivatives.

PREREQUISITES
  • Understanding of integral calculus, particularly definite and indefinite integrals.
  • Familiarity with trigonometric functions, specifically arcsin and arccos.
  • Knowledge of the properties of derivatives and their applications in calculus.
  • Basic comprehension of constants of integration in mathematical expressions.
NEXT STEPS
  • Study the properties of inverse trigonometric functions, focusing on arcsin and arccos.
  • Explore the concept of constants of integration in calculus to understand their implications in solutions.
  • Review advanced integral calculus techniques, particularly those involving square roots in the integrands.
  • Investigate the relationship between derivatives of inverse functions and their geometric interpretations.
USEFUL FOR

Mathematics students, educators, and anyone studying advanced calculus or working with integrals and trigonometric functions will benefit from this discussion.

maverick_starstrider
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Hey, I'm looking through Goldstein's and I'm looking at equation 3.51 where it basically says

[tex]\int \frac{dx}{\sqrt{\gamma x^2 + \beta x + \alpha}} = \frac{1}{\sqrt{-\gamma} } arccos \left( - \frac{\beta + 2 \gamma x}{\sqrt{\beta^2 - 4 \gamma \alpha} }\right)[/tex]

Every integral book I look at says it should be what he gets except an arcsin function and the argument is positive not negative. but

[tex]arcsin(-x) \neq arccos(x)[/tex]

What am I missing?
 
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maverick_starstrider said:
What am I missing?
You are missing [itex]\pi/2[/itex], which can be absorbed into the (unspecified) constant of integration.

Note that
[tex]\frac{d}{dx}\arccos(-x) = \frac{d}{dx}\arcsin(x) = \frac 1{\sqrt{1-x^2}}[/tex]

and that
[tex]\arccos(-x) - \arcsin(x) = \frac{\pi}2[/tex]
 
Last edited:

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