Trouble with a line in Goldstein

Thus,\arccos(-x) = \arcsin(x) + \frac{\pi}2In summary, the conversation is discussing an equation in Goldstein's book, where an integral is equal to an arccos function. However, other integral books show the same equation with an arcsin function instead and the argument being positive instead of negative. The missing piece is \pi/2, which can be absorbed into the constant of integration. It is also noted that the derivative of arccos(-x) is equal to the derivative of arcsin(x) and that arccos(-x) is equal to arcsin(x) plus \pi/2.
  • #1
maverick_starstrider
1,119
6
Hey, I'm looking through Goldstein's and I'm looking at equation 3.51 where it basically says

[tex]\int \frac{dx}{\sqrt{\gamma x^2 + \beta x + \alpha}} = \frac{1}{\sqrt{-\gamma} } arccos \left( - \frac{\beta + 2 \gamma x}{\sqrt{\beta^2 - 4 \gamma \alpha} }\right) [/tex]

Every integral book I look at says it should be what he gets except an arcsin function and the argument is positive not negative. but

[tex] arcsin(-x) \neq arccos(x) [/tex]

What am I missing?
 
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  • #2
maverick_starstrider said:
What am I missing?
You are missing [itex]\pi/2[/itex], which can be absorbed into the (unspecified) constant of integration.

Note that
[tex]\frac{d}{dx}\arccos(-x) = \frac{d}{dx}\arcsin(x) = \frac 1{\sqrt{1-x^2}}[/tex]

and that
[tex]\arccos(-x) - \arcsin(x) = \frac{\pi}2[/tex]
 
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What is the plot of "Trouble with a line in Goldstein"?

The story follows a young scientist named David Goldstein who is struggling to solve a complex problem in his research. He seeks help from his mentor and colleague, Dr. Rachel Kim, but their relationship is strained due to past conflicts. As David delves deeper into his investigation, he uncovers a conspiracy within their research institution that threatens his career and reputation.

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