Troubleshooting Differentiation Using the Long Formula

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Homework Help Overview

The discussion revolves around differentiating the function f(x) = (1)/(2+x) using the long formula for differentiation, specifically the limit definition. The original poster is attempting to apply the formula but encounters difficulties in simplifying the expression.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to differentiate the function by substituting into the long formula and simplifying the resulting expression. They express confusion about an unresolved 'h' in their final result. Some participants suggest checking for errors in sign and remind the poster to consider the limit as h approaches zero.

Discussion Status

Participants are actively engaging with the original poster's approach, offering suggestions for checking calculations and emphasizing the importance of limits in the differentiation process. There is no explicit consensus on the final outcome, as one participant proposes a potential solution while another does not confirm it.

Contextual Notes

The discussion includes a reminder about the behavior of h as it approaches zero, which is a critical aspect of applying the limit definition of differentiation. There is also mention of using LaTeX for clarity in mathematical expressions.

theBTMANIAC
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Homework Statement

I have to differentiate using the long formula [f(x+h)-f(x)] / (h).


Homework Equations



f(x) = (1)/(2+x), x=2

The Attempt at a Solution



First I wrote [ (1/2+x+h) - (1/2+x) ] / (h). Then I created a common denominator in the numerator. I then made the bottom denominator a fraction.

Code:
(2+x)-(2+x+h)     (1)
___________    x  __
(2+x+h)(2+x)      (h)

I subtracted common variables from the numerator and got.

Code:
   -(h)                (1)
________             x ___ 
[(2+x+h)(2+x)]         (h)

Then I got:

       -(1)
_______________
(2+x+h)(2+x)

But as I expanded the numerator, I found that I couldn't get rid of the last h. What is the problem?

Thank you.
 
Last edited:
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i think you dropped a minus sign

also remember h is tending to zero... so multiple out, then take the limit & you can cancel terms tending to zero
 
note you can write in tex (click on below to see the code)
[tex]\frac{-1}{(2+x)(2+x+h)} = \frac{-1}{(2+x)^2+h(2+x))}[/tex]
 
Thanks for the quick reply.

That would mean the solution to this particular problem is [tex]- \frac{1}{16}?[/tex]
 
Yes.
 

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