For example, when you have a function that describes the amount of water (liters) in a cup relative to time (the amount fluctuates for whatever reason). If you wanted to find the average amount of water in the cup in the interval [a,b], you would take the integral of the function in that interval and divide by (b-a). The result can be interpreted as the average amount of liters in the cup in the interval, so you would write the unit as liters, but would the true unit be liters*time? If I were to remove the 1/(b-a) factor, would liters*time would be the true unit? Thanks!