For example, when you have a function that describes the amount of water (liters) in a cup relative to time (the amount fluctuates for whatever reason). If you wanted to find the average amount of water in the cup in the interval [a,b], you would take the integral of the function in that interval and divide by (b-a).(adsbygoogle = window.adsbygoogle || []).push({});

The result can be interpreted as the average amount of liters in the cup in the interval, so you would write the unit as liters, but would the true unit be liters*time? If I were to remove the 1/(b-a) factor, would liters*time would be the true unit?

Thanks!

**Physics Forums - The Fusion of Science and Community**

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# B True unit of average integral result

Have something to add?

Draft saved
Draft deleted

Loading...

Similar Threads - True unit average | Date |
---|---|

I Finding a unit normal to a surface | Sep 13, 2017 |

Extreme Value Theorem true for constants? | Aug 28, 2014 |

Is this true about integrals? | Oct 4, 2013 |

Is that true ? | Jan 10, 2012 |

Is this weird limit true? | Dec 21, 2011 |

**Physics Forums - The Fusion of Science and Community**