Trying to find the appropriate motor for a sliding door

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SUMMARY

The discussion focuses on selecting an appropriate motor for a sliding door system weighing 80kg, requiring precise mechanical calculations. The total force exerted by the doors is 1568 Newtons, with a rolling coefficient of 0.001, resulting in a necessary pulling force of approximately 1.5696 Newtons. The torque required for the belt pulley, with a diameter of 3 cm, is calculated to be 0.047088 N·m. The participant seeks advice on whether to ignore excess torque from available motors, which typically exceed 1 N·m, and how to effectively reduce RPM while increasing torque through gear ratios.

PREREQUISITES
  • Understanding of mechanical calculations for torque and force
  • Familiarity with gear ratios and their effect on motor output
  • Knowledge of rolling coefficients in mechanical systems
  • Basic principles of motor specifications, including RPM and torque ratings
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  • Research gear ratio calculations to optimize motor RPM and torque
  • Explore motor selection criteria for sliding door applications
  • Investigate safety standards related to torque limits in mechanical systems
  • Learn about the impact of rolling coefficients on mechanical efficiency
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Mechanical engineers, product designers, and anyone involved in the design and implementation of automated sliding door systems.

CuriousNotion
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My assignment is to create a sliding door with working motor,mechanical and structure calculations. However I keep having trouble when finding the appropriate motor for the sliding door movement. The doors are both 80kg (Which is 784 Newtons). The entire weight is taken is supported by the track with steel wheels that is connected to a steel rail (to prevent the pulling of the driving belt, altogether it is 1568 Newtons for the doors). this the rolling co-efficient of the steel wheels to steel rails is around 0.001.

So the force needed for the belt to pull the door is

F.c = (1568 x 0.001)=1.5696N

The diameter of the belt pulley is 3 cm so the torque needed is

Torque=force x radius = 1.5696 x 0.03 =0.047088 (N/m)Newton-metres.

Nearly all the motors I have found are over 1 (N/m) of torque but very high rpm (which I need to convert to a lower rpm which , if achieved by gear ratios ,increases the torque further. What should I do? Are my calculations wrong. is the rolling coefficient unrealisic? and is all is correct is okay to ignore a torque that is far more than that required?
 
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Ignoring the torque problem will be fine as long as the new calculated torque isn't strong enough to hurt somebody.
 

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