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Trying to understand the question: Find dy/dx

  1. Mar 3, 2009 #1
    Hello!

    Question asks: Find dy/dx. Do not simplify.

    y = sec(cube root x)

    My answer is

    dy/dx = sec(cube root x) * tan(cube root x)

    Am I correct?

    thanks!
     
  2. jcsd
  3. Mar 3, 2009 #2
    Hello ugeous. You are VERY close. Remember the chain rule? Our inside angle for sec in y = sec (cube root x) is cube root x. you must take the derivative of this "inside angle" to complete the problem correctly.
     
  4. Mar 3, 2009 #3
    Oh, right!

    sec(cube root x) * tan(cube root x) * 1/3(x^-2/3)

    Is this correct?
     
  5. Mar 3, 2009 #4
    You betcha :)
     
  6. Mar 3, 2009 #5
    Thanks man!
     
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