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Killua Rafiq said:Homework Statement:: Hi guys,i want to share with you my project about advanced physics-Physics olimpiads.I find 5 hard problems and solved these.I think it will be useful for students who prepares to olimpiad's and interests in adv physics.Have fun.
Relevant Equations:: $P=\rho gl$,$GM=gR^2$(and etc.)
Pdf is below.
kuruman said:Your solution to Problem 1 is incorrect. It should be $$\frac{l_1}{l_2}=\frac{\tan\theta-\mu_2}{\tan\theta-\mu_1}.$$
No.It was test and there wasn't variant you said.I explained this problem.There $\mu_2 > \mu_1$.Try to solve againkuruman said:Your solution to Problem 1 is incorrect. It should be $$\frac{l_1}{l_2}=\frac{\tan\theta-\mu_2}{\tan\theta-\mu_1}.$$
I wrote same,bruhkuruman said:I messed up an overall negative sign and the correct solution should be $$\frac{l_1}{l_2}=\frac{\mu_2-\tan\theta}{\tan\theta-\mu_1}.$$You have $$\frac{l_1}{l_2}=\frac{\mu_2\tan\theta}{\tan\theta-\mu_1}.$$Did you omit the sign between ##\mu_2## and ##\tan\theta##?
Also, please familiarize how to use LaTeX here. You need two $ instead of one. Also you can use ## for inline equations.
The answer should be $$\frac{\mu_2 tan\theta}{tan\theta -\mu_1}$$Killua Rafiq said:I wrote same,bruh
@etotheipin @kruman i am so sorry.I forgot just add "-".Killua Rafiq said:I wrote same,bruh
It's OK. We all make mistakes.Killua Rafiq said:@etotheipin @kruman i am so sorry.I forgot just add "-".
kuruman said:Your solution to Problem 1 is incorrect. It should be $$\frac{l_1}{l_2}=\frac{\tan\theta-\mu_2}{\tan\theta-\mu_1}.$$
Edit:The answer must be in first problem :$$\frac{\mu_2-tan\theta}{tan\theta-\mu_1}$$Killua Rafiq said:Homework Statement:: Hi guys,i want to share with you my project about advanced physics-Physics olimpiads.I find 5 hard problems and solved these.I think it will be useful for students who prepares to olimpiad's and interests in adv physics.Have fun.
Relevant Equations:: $P=\rho gl$,$GM=gR^2$(and etc.)
Pdf is below.
kuruman said:It's OK. We all make mistakes.
But in ishoterm "T" is const.I wanted to specify that ishotermal and aidabatic similar except adiabatic prosses gives eneregy only with work.And i am agree with you.I will fix problemskuruman said:While I have your attention, check your solution to Problem 5. The process A-B is adiabatic. Near the end of your solution you say that it is a isotherm. That is simply not true. I suggest that you correct this and post a corrected version of the pdf.
Agreed Totally.Check it https://www.physicsforums.com/threads/turkish-tubitak-olympiads-problems-with-solutions-by-rafiq-abbasov-fi.992496/kuruman said:The isothermal and the adiabatic processes are quite different and I would not call them similar. In an isothermal process the temperature does not change and the work done by the gas is equal to the heat that enters the gas. In an adiabatic process, no heat enters the gas and the temperature drops or increases depending on whether the gas is doing positive or negative work. The Carnot cycle is an example of the use of two isotherms and two adiabats to get the highest possible efficiency.
All bugs are not fixed. In the solution to Problem 5 (this version), you claim that in an adiabatic process the temperature does not change. That is not true. It could be true for a solid that does not change its volume when heat is added to it. A gas can expand (or contract) and do positive (or negative) work on the environment. As you know, according to the first law ##\Delta U=Q-W##, where ##W## is the work done by the gas, ##Q## is the heat that enters the gas and ##\Delta U## is the change in internal energy of the gas. In an adiabatic process, ##Q=0## so that ##\Delta U=-W##. This says that if the gas expands adiabatically and does positive work as is the case in Problem 5, the internal energy and hence the temperature must decrease.Killua Rafiq said:Homework Statement:: Again me.All bugs fixed
Relevant Equations:: &&P=\rho gl$$
$$E=mc^2$$
There is no reason to be rude like this.Dude,i remember i wrote T=constant in previous document?. There was ishoterm because of i confused and i was exhausted.So i forgot change this.I know kinda most part adv physics but it was my first article.I will fix this.kuruman said:All bugs are not fixed. In the solution to Problem 5 (this version), you claim that in an adiabatic process the temperature does not change. That is not true. It could be true for a solid that does not change its volume when heat is added to it. A gas can expand (or contract) and do positive (or negative) work on the environment. As you know, according to the first law ##\Delta U=Q-W##, where ##W## is the work done by the gas, ##Q## is the heat that enters the gas and ##\Delta U## is the change in internal energy of the gas. In an adiabatic process, ##Q=0## so that ##\Delta U=-W##. This says that if the gas expands adiabatically and does positive work as is the case in Problem 5, the internal energy and hence the temperature must decrease.
Basic stuff like this must be clear in your mind before you attempt Olympiad-level problems.
Killua Rafiq said:There is no reason to be rude like this.Dude,remember i wrote T=constant in previous document?. There was ishoterm because of i confused and i was exhausted.So i forgot change this.I know kinda most part adv physics but it was my first article.I will fix this.
The Turkish Tubitak olympiads are a series of science and mathematics competitions organized by the Scientific and Technological Research Council of Turkey (Tubitak) for high school students. These olympiads cover various subjects such as physics, chemistry, biology, mathematics, and computer science.
Rafiq Abbasov is a renowned mathematician and educator who has written numerous books and articles on mathematics and participated in various international mathematics competitions. He is also known for his contributions to the Turkish Tubitak olympiads, where he has provided problems and solutions for many years.
The problems in the Turkish Tubitak olympiads are usually challenging and require creative thinking and problem-solving skills. They cover a wide range of topics and often involve real-life scenarios and applications of scientific concepts.
Studying the problems and solutions by Rafiq Abbasov can help students improve their problem-solving skills and gain a deeper understanding of the subjects covered in the Turkish Tubitak olympiads. It can also serve as a valuable resource for students preparing for similar competitions or exams.
No, the solutions provided by Rafiq Abbasov are not the only correct answers to the problems in the Turkish Tubitak olympiads. There may be multiple ways to approach and solve a problem, and students are encouraged to come up with their own solutions. The solutions provided by Rafiq Abbasov are meant to serve as a guide and reference for students.