Two Balls Thrown Vertical Upward

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SUMMARY

The discussion centers on the physics of two balls thrown vertically upward from different heights and initial speeds, specifically analyzing which ball hits the ground first. The first ball is thrown from a height of 50 feet with an initial speed of 40 ft/sec, while the second ball is thrown from 100 feet with an initial speed of 5 ft/sec. The height of each ball over time is described by the equation h(t) = -16t² + v₀t + h₀. To determine the time of impact for each ball, the quadratic formula is applied, leading to the conclusion that the ball with the smaller time value will hit the ground first.

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  • #31
Ok. Great. Let us move on. I will post similar word problems in the coming days.
 
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  • #32
Okay, so we've found:

$$t=\frac{v_0\pm\sqrt{v_0^2-2a\Delta x}}{a}$$

Suppose we have $\Delta x=0$. At what times does that occur?
 
  • #33
MarkFL said:
Okay, so we've found:

$$t=\frac{v_0\pm\sqrt{v_0^2-2a\Delta x}}{a}$$

Suppose we have $\Delta x=0$. At what times does that occur?

Replace (delta)x with 0 and simplify, right?
 
  • #34
RTCNTC said:
Replace (delta)x with 0 and simplify, right?

Yes. :)
 
  • #35
Thank you for all your help.
 
  • #36
Um, okay.

I was attempting to share with you some of the ways I used to go about learning things that helped me succeed in my math studies, but if you just wish to walk away from that, then so be it. Examining formulas at the boundaries of the parameter values gave me a good number of "aha" moments. Looking at how one values changes in relation to another is also illuminating.

images
 
  • #37
MarkFL said:
Um, okay.

I was attempting to share with you some of the ways I used to go about learning things that helped me succeed in my math studies, but if you just wish to walk away from that, then so be it. Examining formulas at the boundaries of the parameter values gave me a good number of "aha" moments. Looking at how one values changes in relation to another is also illuminating.

I thank you for helping me as I march on my way to succeed with word problems.
 

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