1. The problem statement, all variables and given/known data An 8kg block rests on an inclined plane where theta=37 degrees. The coefficient of kinetic friction on the plane is .23. The 8kg block is connect by a massless, frictionless pully to a hanging 16kg block. The blocks are released from rest. What is the acceleration. 2. Relevant equations I think F=ma 3. The attempt at a solution So I used F=ma for each block. 8kg block. T-sin(37)*8*9.8-cos(37)*8*9.8*.23=8*a eq1 16kg block. T-9.8*16=-16*a eq2 so eq1-eq2 = 9.8*16-sin(37)*8*9.8-cos(37)*8*9.8*.23=24a. so 95.2=24a leaving a=3.97. When we checked the answer it said a = 1.3. What are we doing wrong???